what is the measure of angle j in the triangle below? hint:Law of Sines A.78 degrees B.51.5 degrees C.35 degrees or D. cannot be determined.

To find the measure of angle J, we would apply the sine rule which is expressed as
a/sinA = b/sinB = c/SinC
where
A, B and C are the angles in the triangle
a, b and c are the length of the sides opposite each respective angle.
By applying this rule to the given triangle, we have
l = JK = 15
L = 102
j = KL = 12
J = ?
Thus, we have
15/Sin102 = 12/SinJ
By crossmultiplying, we have
15SinJ = 12Sin102
Dividing both sides by 15,
SinJ = 12Sin102/15
SinJ = 0.7825
We would find the sine inverse of 0.7825
J = Sin^-1(0.7825)
J = 51.5 degrees