Answer::
[tex]\frac{3}{5}x+2[/tex]
Explanation:
Given the sum:
[tex]\left(\frac{2}{5} x+3\right)+\left(\frac{1}{5} x-1\right)[/tex]
First, remove the brackets:
[tex]=\frac{2}{5}x+3+\frac{1}{5}x-1[/tex]
Next, rearrange to bring like terms together, i.e. bring all the numbers without any letter (variable) attached together.
[tex]={\frac{2}{5}}x+\frac{1}{5}x+3-1[/tex]
We can then add the like terms:
Using the diagram below:
This means that:
[tex]\begin{gathered} \frac{2}{5}+\frac{1}{5}=\frac{3}{5} \\ \frac{2}{5}x+\frac{1}{5}x=\frac{3}{5}x \end{gathered}[/tex]
So, we then have:
[tex]\frac{2}{5}x+\frac{1}{5}x+3-1=\frac{3}{5}x+2[/tex]
The sum of the expression is:
[tex]\frac{3}{5}x+2[/tex]
