Respuesta :

Answer

[tex](\frac{\pi}{4},\sqrt{72})[/tex]

Explanation

Using Pythagoras Theorem, we have:

[tex]\begin{gathered} x=\sqrt{6^2+6^2} \\ x=\sqrt{72} \end{gathered}[/tex]

And as that point has 6 and 6, must be an

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