ANSWER:
Smallest piece = 12 in
Longest piece = 36 in
Third piece = 24 in
STEP-BY-STEP EXPLANATION:
We have the following:
Let x = smallest piece
Let y = longest piece
Let z = third piece
We can propose the following system of equations:
[tex]\begin{gathered} x+y+z=72\text{ (1)} \\ x=\frac{1}{3}y\text{ (2)} \\ z=y-12\text{ (3)} \end{gathered}[/tex]We replace equations 2 and 3 in 1, and solving for y:
[tex]\begin{gathered} \frac{1}{3}y+y+y-12=72 \\ \frac{1}{3}y+2y=72+12 \\ y+3\cdot2y=3\cdot84 \\ 7y=252 \\ y=\frac{252}{7} \\ y=36\text{ in} \end{gathered}[/tex]Now, for x and y:
[tex]\begin{gathered} x=\frac{1}{3}\cdot36=12\text{ in} \\ z=36-12=24\text{ in} \end{gathered}[/tex]