As given:
[tex]\frac{\frac{-3}{8}}{\frac{-1}{2}}[/tex]As we know that:
[tex]\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\times d}{b\times c}[/tex]So:
[tex]\begin{gathered} \frac{-3\times2}{8\times-1}=\frac{3\times2}{8}=\frac{3}{4} \\ \end{gathered}[/tex]