Question

A- The area of a rectangular field is 8712 m2 . If the width of the field is 88 m, what is its length? B- The perimeter of a rectangular painting is 296 cm. If the length of the painting is 83 cm, what is its width?

Answer 1

$A)\:l=99m\:B)w=65cm$

A) Since we know the formula for the area of a rectangle, then we can do the following to find the length of this rectangular area: plug into the area formula the given data and solve for l:

$\begin{gathered} A=l\times w \\ l\times w=A \\ \\ 88l=8712m^2 \\ \\ \frac{88l}{88}=\frac{8712}{88} \\ \\ l=99\:m \end{gathered}$

B) On the other hand, we can also derive a formula for the Perimeter:

$\begin{gathered} P=2(l+w) \\ \\ 2(l+w)=296 \\ \\ 2(83+w)=296 \\ \\ 166+2w=296 \\ \\ 2w=296-166 \\ \\ 2w=130 \\ \\ \frac{2w}{2}=\frac{130}{2} \\ \\ w=65\:cm \end{gathered}$

Thus, these are the answers.