Question

I can't find the cos of A tan of B or sin of A

Answer 1

$\cos (A)=\frac{3\sqrt[]{10}}{10}or(0.9486),\text{ tan(B) =3, sin(A)=}\frac{\sqrt[]{10}}{10}\text{ or (0.3162)}$

1) Let's find out those trigonometric ratios:

2) In this triangle, based upon their definitions we can write:

$\begin{gathered} \cos (A)=\frac{15}{5\sqrt[]{10}}\cdot\frac{\sqrt[]{10}}{\sqrt[]{10}}=\frac{15\sqrt[]{10}}{50}=\frac{3\sqrt[]{10}}{10} \\ \tan (B)=\frac{15}{5}=3 \\ \sin (A)=\frac{5}{5\sqrt[]{10}}=\frac{5\sqrt[]{10}\cdot\sqrt[]{10}}{5\sqrt[]{10}\cdot\sqrt[]{10}}=\frac{\sqrt[]{10}}{10} \end{gathered}$

• Notice that the hypotenuse is always on the opposite side to the right angle.

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• The notion of an adjacent, opposite leg depends on the angle you refer to.