you take out a loan for $702 at an annual interest rate of 6% compounded quarterly for 2 years what is the total amount that you will have at the end of the two-year
we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]where
A is the total amount at the end of two years
P is the loan
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
P=$702
r=6%=6/100=0.06
t=2 years
n=4
substitute the given values in the formula
[tex]\begin{gathered} A=702\cdot(1+\frac{0.06}{4})^{4\cdot2} \\ A=702\cdot(1.015)^8 \\ A=\$790.80 \end{gathered}[/tex]therefore
the answer is