Question

Simplify (sqrt)98m^12Using factor tree. Please draw. Quick answer = amazing review. Not a graded or timed assessment

Answer 1

We can directly remove m^12 from the square root, and stay only with 98 inside the square root

$\sqrt[]{98m^{12}}=m^{\frac{12}{2}}\sqrt[]{98}=m^6\sqrt[]{98}$

Therefore

$\sqrt[]{98m^{12}}=m^6\sqrt[]{98}$

Now we can just factor 98 inside the square root:

Then

$98=2\cdot7^2$

We can put it inside the square root

$\begin{gathered} m^6\, \sqrt[]{98}=m^6\, \sqrt[]{2\cdot7^2} \\ \\ \end{gathered}$

Now we can simplify the square with the square root

$m^6\, \sqrt[]{2\cdot7^2}=7m^6\, \sqrt[]{2}$

That's the final result

$\sqrt[]{98m^{12}}=7m^6\, \sqrt[]{2}$