Triangle ABC undergoes a translation of 5 units up and 1 unit to the right resulting translation A'B'C'. What are the coordinates for the new verticals HELP MEEE

The coordinates of the new vertices are;
[tex]undefined[/tex]Here, we want to perform a translation and write the coordinates of the new points
Before we do this, we need to know the trnaslation rule involved
Translating 5 units up mean we add 5 to the y-axis value. Translating 1 unit up mean we will add 1 unit to the x-axis value
We have the rule as follows;
[tex](x,y)\rightarrow(x+1,y+5)_{}[/tex]Therefore, for the points given, we have that;
[tex]\begin{gathered} A^{\prime}\text{ = (3+1, 4 + 5) = (4,9)} \\ B^{\prime}\text{ = (0+1, 2 + 5) = (1,7)} \\ C^{\prime}\text{ = (1+1 , 7 + 5) = (2,12)} \end{gathered}[/tex]