The expression
[tex]\frac{w^8}{w^2}^{}[/tex]using the property of exponents that
[tex]\textcolor{#FF7968}{\frac{a^x}{a^y}=a^{x-y}}[/tex]we simplify to
[tex]\frac{w^8}{w^2}=w^{(8-2)}[/tex][tex]\rightarrow\textcolor{#FF7968}{w^6}\text{\textcolor{#FF7968}{.}}[/tex]which is our answer.
