Find each product and then write answer in standard form

SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given problem
[tex](-2-3i)(-2+3i)[/tex]STEP 2: Find the product of the two factors
[tex]\begin{gathered} (-2-3i)\times(-2+3i) \\ \mathrm{Apply\: complex\: arithmetic\: rule}\colon\quad \mleft(a+bi\mright)\mleft(a-bi\mright)=a^2+b^2 \\ a=-2,\: b=-3 \\ =\mleft(-2\mright)^2+\mleft(-3\mright)^2 \\ =4+9 \\ =13 \end{gathered}[/tex]Hence, the product of the two complex numbers gives 13