Use the rational zero theorem to list all possible rational zero's for the polynomial function: f(x)=2x^3+3x^2-8x+5 To earn full credit please share all work, calculations and thinking. If you prefer you can do the work by hand on a piece of paper, take a picture of that work and upload it.

Use the rational zero theorem to list all possible rational zeros for the polynomial function fx2x33x28x5 To earn full credit please share all work calculations class=

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The given polynomial function is:

[tex]f(x)=2x^3+3x^2-8x+5[/tex]

Since all the co-efficients are integers, we can apply the rational zero theorem.

The trailing co-efficient ( the co-efficient of the constant term) is 5.

Find its factors with the plus and minus sign; thus we have;

[tex]\begin{gathered} \text{Factors}=\pm1,\pm5 \\ \text{These are the possible values for p} \end{gathered}[/tex]

The leading co-efficient ( the co-efficient of the term with the highest degree) is 2.

Find its factors with the plus and minus sign; thus we have:

[tex]\begin{gathered} \text{Factors}=\pm1,\pm2 \\ \text{These are the }possible\text{ values for q} \end{gathered}[/tex]

Next, is finding all possible values for the rational expression p/q. Thus, we have:

[tex]\begin{gathered} \frac{p}{q}=\pm\frac{1}{1},\pm\frac{1}{2},\pm\frac{5}{1},\pm\frac{5}{2} \\ \frac{p}{q}=\pm1,\pm\frac{1}{2},\pm5,\pm\frac{5}{2} \end{gathered}[/tex]

Hence, the possible rational zeros for the polynomial function are:

[tex]\pm1,\pm\frac{1}{2},\pm5,\pm\frac{5}{2}[/tex]

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