The following thermochemical equation is for the reaction of H2O2(I) to form H2O(I) and O2(g)

7.08 grams
Given the reaction below;
[tex]2H_2O_2\rightarrow2H_2O+O_2\text{ }\triangle H=-196kJ[/tex]The reaction shows that 2 moles of 2O2 releases 196kJ of energy. Hence 1 moles of H2O2 will. release 98kJ of energy (196/2).
In order to create 20.4kJ of energy, we will need;
[tex]moles\text{ of }H_2O_2=\frac{20.4}{98}=0.2082\text{ moles}[/tex]Detemine the mass of H2O2
[tex]\begin{gathered} Mass=mole\times molar\text{ mass} \\ Mass\text{ of H}_2O_2=0.2082\times34.02 \\ Mass\text{ of H}_2O_2=7.08grams \end{gathered}[/tex]Hence the mass of H2O2 that will react is 7.08 grams