we have
x = adult tickets
y = children tickets
and the equations
x + y = 60
11x + 6y = 460
then solve the system:
[tex]\begin{gathered} x+y=60 \\ x+y-y=60-y \\ x=60-y \\ \text{then} \\ 11(60-y)+6y=460 \\ 660-11y+6y=460 \\ 660-5y=460 \\ 660-5y-660=460-660 \\ -5y=-200 \\ -\frac{5y}{-5}=-\frac{200}{-5} \\ y=40 \end{gathered}[/tex]and for x
[tex]x=60-40=20[/tex]answer: 20 adult tickets and 40 children tickets