Question

light Incident on air / Glass boundary If the Incident angle IS 42°the Index of refraction of the glass 1.5 what the Refracted angle

Answer 1

Given

The incident angle is

$i=42^o$

The index of refraction is n=1.5

To find

The angle of refraction

Explanation

We know,

$\begin{gathered} n=\frac{sini}{sinr} \\ \Rightarrow1.5=\frac{sin42^0}{sinr} \\ \Rightarrow sinr=\frac{sin42^o}{1.5} \\ \Rightarrow sinr=0.44 \\ \Rightarrow r=26.10^o \end{gathered}$

Conclusion

The angle of refraction is 26.10 deg