Respuesta :

For an arithmeticsequence whose first term is a_1 and the common difference is d, the nth term would be;

[tex]a_n=a_1+(n-1)d[/tex]

Therefore, where the indicated term is the 50th term, we would have;

[tex]\begin{gathered} a_1=9,d=2 \\ a_{50}=9+(50-1)2 \\ a_{50}=9+(49)2 \\ a_{50}=9+98 \\ a_{50}=107 \end{gathered}[/tex]

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