Question

What is the magnitude of a vector if the x component is -12m and the y component is -9.2m

Answer 1

Answer:

15.12 m

Explanation:

The magnitude of a vector (x, y) can be calculated as

$\sqrt{x^2+y^2}$

So, replacing x by -12 m and y by -9.2 m, we get

$\begin{gathered} \sqrt{(-12)^2+(-9.2)^2} \\ \sqrt{144+84.64} \\ \sqrt{228.64} \\ 15.12\text{ m} \end{gathered}$

Therefore, the magnitude of the vector is 15.12 m