Respuesta :

Answer

[tex]x=\frac{\pi}{12}+n\pi.\text{ Option D is correct.}[/tex]

Explanations:

Given the trigonometry equation expressed as;

[tex]sinxcosx=\frac{1}{4}[/tex]

We are to simplify for the value(s) of 'x"

Recall from trigonometry identity that:

[tex]\begin{gathered} Sin2x=2sinxcosx \\ sinxcosx=\frac{sin2x}{2} \end{gathered}[/tex]

Substitute the result into the original equation to have:

[tex]\begin{gathered} \frac{sin2x}{2}=\frac{1}{4} \\ sin2x=\frac{1}{2} \end{gathered}[/tex]

Solve for the value of "x"

[tex]\begin{gathered} 2x=sin^{-1}(\frac{1}{2}) \\ 2x=30^0 \\ x=\frac{30}{2} \\ x=15 \\ x=\frac{\pi}{12} \\ \end{gathered}[/tex]

The general solution to the given trigonometry function is:

[tex]x=\frac{\pi}{12}+n\pi[/tex]

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