We will have the expression:
[tex]w^2-\frac{3}{2}w+x=()^2[/tex]We know that the (-3/2) has to be the result of:
[tex]2(a)(b)[/tex]Where a is the value besides w^2 and b is the other value, then we solve for it, that is:
[tex]2(1)(b)=-\frac{3}{2}\Rightarrow b=-\frac{3}{4}[/tex]So, our expression would take the shape:
[tex]w^2-\frac{3}{2}w+\frac{9}{16}=(w-\frac{3}{4})^2[/tex]