Pls help.. im stuck on the setup of the problem .

Given the right angle triangle ABC
As shown, there is a line segment perpendicular to the base AC that produces another two right-angle triangles
From the similarity of the triangle:
[tex]\begin{gathered} \frac{x}{7}=\frac{7}{13} \\ \\ x=\frac{7\cdot7}{13}=3.76923 \end{gathered}[/tex]Rounding to the nearest tenths
So, the answer will be:
[tex]x=3.8[/tex]Now, we will find the length of AC
as shown:
[tex]\begin{gathered} AC=x+13=3.8+13 \\ \\ AC=16.8 \end{gathered}[/tex]