The equation is given as
[tex]\begin{gathered} a.x^2+7x-11=0 \\ b.3x^2-5x-9=0 \end{gathered}[/tex]Explanationa. The equation is given as
[tex]x^2+7x-11=0[/tex]The general equation is
[tex]ax^2+bx+c[/tex]The sum of the root is determined as
[tex]\frac{-b}{a}[/tex]Substitute the values from the given equation.
[tex]-\frac{b}{a}=-\frac{7}{1}[/tex]The product of roots is determined as
[tex]\frac{c}{a}[/tex]Substitute the values from the given equation.
[tex]\frac{c}{a}=-\frac{11}{1}=-11[/tex]b. The equation is given
[tex]3x^2-5x-9=0[/tex]The sum of root is
[tex]\frac{-b}{a}=-\frac{-5}{3}=\frac{5}{3}[/tex]The product of root is
[tex]\frac{c}{a}=-\frac{9}{3}=-3[/tex]Answera. The sum of root is -7.
The product of root is -11.
b. The sum of root is 5/3.
The product of root is -3.