Respuesta :

Given

The equation is given as

[tex]\begin{gathered} a.x^2+7x-11=0 \\ b.3x^2-5x-9=0 \end{gathered}[/tex]Explanation

a. The equation is given as

[tex]x^2+7x-11=0[/tex]

The general equation is

[tex]ax^2+bx+c[/tex]

The sum of the root is determined as

[tex]\frac{-b}{a}[/tex]

Substitute the values from the given equation.

[tex]-\frac{b}{a}=-\frac{7}{1}[/tex]

The product of roots is determined as

[tex]\frac{c}{a}[/tex]

Substitute the values from the given equation.

[tex]\frac{c}{a}=-\frac{11}{1}=-11[/tex]

b. The equation is given

[tex]3x^2-5x-9=0[/tex]

The sum of root is

[tex]\frac{-b}{a}=-\frac{-5}{3}=\frac{5}{3}[/tex]

The product of root is

[tex]\frac{c}{a}=-\frac{9}{3}=-3[/tex]Answer

a. The sum of root is -7.

The product of root is -11.

b. The sum of root is 5/3.

The product of root is -3.

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