ANSWER
at Z = -1.15, serum HDL levels (x) = 65.76
at Z = 2.95, serum HDL levels (x) = 80.52
STEP BY STEP EXPLANATION
Step 1: at Z = -1.15
[tex]\begin{gathered} z-\text{score = }\frac{data\text{ value - mean}}{s\tan dard\text{ deviation}} \\ -1.15\text{ = }\frac{x\text{ - 69.9}}{3.6} \\ x\text{ - 69.9 = -1.15}\ast3.6 \\ x\text{ = -4.14 + 69.9} \\ x\text{ = 65.76} \end{gathered}[/tex]
Step 2: at Z = 2.95
[tex]\begin{gathered} 2.95\text{ = }\frac{x\text{ - 69.9}}{3.6} \\ x\text{ - 69.9 = 2.95}\ast3.6 \\ x\text{ = 10.65 + 69.9} \\ x\text{ = 80.52} \end{gathered}[/tex]