Let us locate the points of the parallelogram
[tex]\begin{gathered} K(-3,7)\rightarrow K^{\prime}(3,3) \\ J(-6,5)\rightarrow J^{\prime}(6,1) \\ M(-6,-3)\rightarrow M^{\prime}(6,-7) \\ L(-3,-1)\rightarrow L^{\prime}(3,-5) \\ \text{The rule is } \\ (x,y)\rightarrow(-x,y-4) \end{gathered}[/tex]
