Question

Cyanide gas has a pressure of 6.0atm.If the pressure is decreased to 0.5atm and the final volume is 48L, what was the original volume?

Answer 1

ANSWER

The original volume of the gas is 4L

EXPLANATION

Given information

The initial pressure of the gas = 6.0atm

The final pressure of the gas = 0.5 atm

The final volume of the gas = 48L

Step 1: Write the Boyle's law formula

$\text{ P1}\times V1\text{ = P2}\times V2$

Where

P1 = 6.0 atm

P2 = 0.5 atm

V2 = 48L

V1 =?

Step 2: Substitute the given data into the formula in step 1

$\begin{gathered} 6.0\times V1\text{ = 0.5}\times\text{ 48} \\ 6.0\text{ }\times\text{ V1 = 24} \\ \text{ Divide both sides by 6} \\ \text{ V1 = }\frac{24}{6} \\ \text{ V1 = 4L} \end{gathered}$

Hence, the original volume of the gas is 4L