first solve the parenthesis multiplying by each coefficient
[tex]\begin{gathered} (2\times9a)+(2\times3)+(-1\times11a)+(-1\times-2) \\ 18a+6-11a+2 \end{gathered}[/tex]now group and operate
[tex]\begin{gathered} (18-11)a+(6+2) \\ 7a+8 \end{gathered}[/tex]the equivalent expression is 7a+8