ANSWER
Option D
[tex]15\frac{1}{3}\text{ X 8}\frac{1}{2}[/tex]EXPLANATION
Given:
[tex]\begin{gathered} \text{The length }of\text{ the garden = 7}\frac{2}{3} \\ \text{Width of the garden = 4}\frac{1}{4} \end{gathered}[/tex]Note: To double the dimensions of the garden means to double both length and width of the garden.
Double the Length
[tex]\begin{gathered} 7\frac{1}{3}\text{ + 7}\frac{1}{3} \\ \frac{23}{3}+\frac{23}{3} \\ \text{ find the LCM} \\ \frac{23\text{ + 23}}{3} \\ \frac{46}{3} \\ =\text{ 15}\frac{1}{3} \end{gathered}[/tex]Double the Width
[tex]\begin{gathered} 4\frac{1}{4}+\text{ 4}\frac{1}{4} \\ =\text{ }\frac{17}{4}+\text{ }\frac{17}{4} \\ \text{ Find the LCM} \\ =\text{ }\frac{17\text{ + 17}}{4} \\ \text{ = }\frac{34}{4} \\ \text{ = 8}\frac{1}{2} \end{gathered}[/tex]Hence, the dimensions of the garden if the garden is double is:
[tex]15\frac{1}{3}\text{ X 8}\frac{1}{2}[/tex]