ANSWER:
[tex](\frac{40}{13},-\frac{15}{13})[/tex]STEP-BY-STEP EXPLANATION:
We have the following system of equations
[tex]\begin{gathered} 2x+y=5 \\ 3x-5y=15 \end{gathered}[/tex]solving the system by substitution
[tex]\begin{gathered} 2x+y=5\rightarrow y=5-2x \\ 3x-5\cdot(5-2x)=15 \\ 3x-25+10x=15 \\ 13x=15+25 \\ x=\frac{40}{13} \end{gathered}[/tex]replacing x in y
[tex]y=5-2\cdot\frac{40}{13}=-\frac{15}{13}[/tex]The solution is:
[tex](\frac{40}{13},-\frac{15}{13})[/tex]