Answer
Explanations:
The formula for calculating the percent impurity of oxygen is expressed as:
[tex]\%O=\frac{mass\text{ of oxygen}}{Mass\text{ of water}}\times100[/tex]
Given the following parameter
Mass of water = 36.8 grams
Determine the moles of water
According to the ideal gas equation, PV = nRT
[tex]\begin{gathered} n=\frac{PV}{RT} \\ n=\frac{1atm\times64L}{0.08205\times273K} \\ n=\frac{64}{22.399} \\ n=2.857moles \end{gathered}[/tex]
Determine the mass of oxygen
Mass of O2 = moles * molar mass
Mass of O2 = 2.857 * 16
Mass of O2 =
