Since we know that tanx=5, we can find the angle easily using the inverse function:
[tex]\begin{gathered} \tan x=5 \\ \Rightarrow x=\tan ^{-1}(5)=78.69 \\ x=78.69 \end{gathered}[/tex]We have then that the angle is x = 78.69°, now we only find the value of cosine and sine:
[tex]\begin{gathered} \cos (78.69)=0.196116\approx\frac{1}{\sqrt[]{26}} \\ \sin (78.69)=0.980581\approx\frac{5}{\sqrt[]{26}} \end{gathered}[/tex]therefore, sinx=5/sqrt(26) and cosx=1/sqrt(26)