One number is 4 more than another number and their sum is 22 to find the numbers

First. One number is 4 more than another number:
The equation will be:
[tex]x+4=y\text{ \lparen1\rparen}[/tex]Second. Their sim is 22:
[tex]x+y=22\text{ \lparen2\rparen}[/tex]We have two equations to solve with any method. Using substitution method, we get:
Repacing (1) in (2):
[tex]x+(x+4)=22[/tex]Solving for x:
[tex]\begin{gathered} x+x+4=22 \\ 2x=22-4 \\ 2x=18 \\ x=\frac{18}{2}=9 \end{gathered}[/tex]Putting x=9 in (1):
[tex]\begin{gathered} y=x+4 \\ y=9+4 \\ y=13 \end{gathered}[/tex]Answer: the number are 9 and 13.