We have to find:
[tex]2^{-4}=?[/tex]By the inverse law of exponents,we have:
[tex]a^{-b}=\frac{1}{a^b}[/tex]where a,b are any numbers.
According to our question,we have a=2 and b=4 here
Putting the values,we get:
[tex]2^{-4}=\frac{1}{2^4}[/tex]Now, we know that
[tex]a^b=a\times a\times a\times a\ldots\ldots..\times a\text{ b times}[/tex]That is,in our question,
[tex]2^4=2\times2\times2\times2=16[/tex]Hence,
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