Question

I need this practice problem answered ASAP Pre calc subject

Answer 1

g(x) = 2∛(x-3) + 4

Write as a linear equation

y= 2∛(x-3) + 4

Swap x and y variables

x = 2∛(y-3) + 4

Solve for y

x - 4 = 2∛(y-3)

(x-4) / 2 = ∛(y-3)

[(x-4) / 2 ] ^3 = y - 3

(x-4)^3 / 8+3 = y

$f(x)=\frac{(x-4)^3}{8}+3$