Question

compare rates in context

Answer 1

We know that

• Satellite B flies 77400 miles in 9 hours.

To find the constant rate of satellite B, let's divide.

$\begin{gathered} r_B=\frac{77400mi}{9h} \\ r_B=8600(\frac{mi}{h}) \end{gathered}$

Satellite B flies 8600 miles per hour.

Satellite A flies 1800 miles per hour because that's its constant rate.

Subtract the rates to find the difference between them.

$8600-1800=6800$

Therefore, Space Explorer B travels 6800 miles more than Space Explorer A in one hour