6. Use the quadratic formula to solve the equation.-3x -x-3-0- 121.135-1t35B- 4135-It170

we have
-3x^2-x-3=0
Using the quadratic formula
we have
a=-3
b=-1
c=-3
substitute in the formula
[tex]x=\frac{-(-1)\pm\sqrt[]{-1^2-4(-3)(-3)}}{2(-3)}[/tex][tex]x=\frac{1\pm\sqrt[]{-35}}{-6}[/tex]Remember that
i^2=-1
so
[tex]x=\frac{1\pm i\sqrt[]{35}}{-6}=x=\frac{-1\pm i\sqrt[]{-35}}{6}[/tex]answer is option B