Question

What is the equation, in point-slope form, of the line thatis parallel to the given line and passes through the point(-3, 1)?3212/27EE2-5 -3 -2 -134O y-1=- }(x + 3)Oy-1=-(x + 3)O y-1= } (x + 3)Oy-1= {(x + 3)(2, 4)Save and ExitNextSubmit

Answer 1

At first, we will find the slope of the given line

As shown the given line passes through the points ( -2, -4 ) and ( 2, 2 )

The slope will be calculated as follows:

$slope=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}=\frac{2-(-4)}{2-(-2)}=\frac{2+4}{2+2}=\frac{6}{4}=\frac{3}{2}$

As we know, the parallel lines have the same slope

So, the slope of the required line = 3/2

The required line passes through the point (-3, 1)

So, the point-slope form of the line will be:

$y-1=\frac{3}{2}(x+3)$

so, the answer will be the last option