We want to solve the following system
[tex]\begin{cases}5x+y=13 \\ 63-4y=26\end{cases}[/tex]First, we're going to solve the second equation for one of the variables.
[tex]\begin{gathered} 63-4y=26 \\ -4y=26-63 \\ -4y=-37 \\ y=\frac{37}{4} \end{gathered}[/tex]Then, we're going to substitute (plug-in) this expression into the other equation and solve.
[tex]\begin{gathered} 5x+(\frac{37}{4})=13 \\ 5x=13-\frac{37}{4} \\ 5x=\frac{52-37}{4} \\ 5x=\frac{15}{4} \\ x=\frac{3}{4} \end{gathered}[/tex]And this is our solution.
[tex](\frac{3}{4},\frac{37}{4})[/tex]