Respuesta :

Answer:

Centre: (2, 1)

Radius: 7

Explanation:

If we have an equation of the form

[tex](x-a)^2+(x-b)^2=r^2[/tex]

then the centre of the circle is located at (a, b) and the radius is r.

Now, in our case we have

[tex]\mleft(x-2\mright)^2+\mleft(y-1\mright)^2=49[/tex]

which can be rewritten as

[tex]\mleft(x-2\mright)^2+\mleft(y-1\mright)^2=7^2[/tex]

which tells us that the centre is at (2, 1) and the radius is 7.

The graph is attached below.

Ver imagen MaximilienR250497

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