Question

Consider the following equilibrium: 3A(g) + 4B(s) ↔ 2C(g) + 2D(g) K = 9.1If the [A] = 2.3 x 10-2 M, [B] = 18.6M, [C] = 0.6 M, [D] = 7.2 x 10-3M, which way must the reaction shift toreach equilibrium?

Answer 1

Answer

K is 9.1 so the reaction will shift to the left side to reach equilibrium.

Explanation

3A(g) + 4B(s) ↔ 2C(g) + 2D(g) K = 9.1

From the equilibrium given, the equilibrium constant K is 9.1 so the equilibrium will shift to the left side favoring reactants formation.

This is because if K is greater than 1, it means the concentrations of the products are greater than those of the reactants and the equilibrium will shift to the reactant side to favor the reactants.