Given:
Initial speed, u = 0 m/s
Final speed = 4 m/s
Time, t = 2 seconds
Given that acceleration remains the same, let's find the speed after 10 seconds.
Apply the formula:
[tex]v=u+at[/tex]Where:
v is the final speed
u is the initial speed
a is the acceleration
t is the time.
Hence, we have the equation:
[tex]4=0+2a[/tex]Let's find the acceleration (a) from the equation above.
Divide both sides by 2:
[tex]\begin{gathered} 4=2a \\ \\ \frac{4}{2}=\frac{2a}{2} \\ \\ 2=a \\ \\ a=2 \end{gathered}[/tex]The acceleration is 2 m/s^2.
After 10 seconds, given that the acceleration is the same, we have:
[tex]\begin{gathered} v=u+at \\ \\ v=0+2(10) \end{gathered}[/tex]Let's solve for the speed v.
[tex]\begin{gathered} v=0+20 \\ \\ v=20\text{ m/s} \end{gathered}[/tex]Therefore, the speed after 10 seconds will be 20 meters per second.
ANSWER:
B. 20 m/s