Given
[tex]\begin{gathered} g(x)=\left|-3x+16\right| \\ \text{Substitute 20 for x in the function, then} \\ g(20)=\left|-3\ast20+16\right| \\ =\left|-60+16\right| \\ =\left|-44\right| \\ =44 \end{gathered}[/tex]The function h(x) is
[tex]\begin{gathered} h(x)=-x^2+8x \\ \text{Substitute 7 for x to get h(7)} \\ h(7)=-7^2+8\ast7 \\ =-49+56 \\ =7 \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} g(20)\text{ +h(7)=}44+7 \\ =51 \end{gathered}[/tex]Therefore, g(20)+h(7)=51
