Given the following equation:
[tex]5y²+30y=0[/tex]We will solve the equation for y as follows:
[tex]\begin{gathered} 5y^2+30y=0 \\ y(5y+30)=0 \\ \\ so,\text{ }y=0 \\ or,\text{ }5y+30=0\to5y=-30 \\ y=\frac{-30}{5}=-6 \end{gathered}[/tex]So, the answer will be:
[tex]y=\lbrace-6,0\rbrace[/tex]