Question

Based on the information in the table, whatis the acceleration of this object?t(s)v (m/s)0.03.01.06.02.01919199.03.012A. 12 m/s2B. 3.0 m/s2C. 6.0 m/s2D. 4.0 m/s2

Answer 1

In order to calculate the acceleration, we can use any two pairs of the table in the formula:

$a=\frac{v_2-v_1}{t_2-t_1}$

Using the points (1, 6) and (2, 9), we have:

$a=\frac{9-6}{2-1}=\frac{3}{1}=3\text{ m/s2}$

Therefore the correct option is B.