First, let's determine the slope and y-intercept of the line to write the equation.
You can calculate the slope of the line using the formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Where
(x₁,y₁) are coordinates of one of the points of the line
(x₂,y₂) are the coordinates of the second point
[tex]\begin{gathered} m=\frac{9-8}{9-6} \\ m=\frac{1}{3} \end{gathered}[/tex]
Using the point-slope form you can determine the equation of the line:
Use m=1/3 and (x₁,y₁) as (6,8)
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-8=\frac{1}{3}(x-6) \end{gathered}[/tex]
-distribute the multiplication on the parentheses term
[tex]\begin{gathered} y-8=\frac{1}{3}\cdot x-\frac{1}{3}\cdot6 \\ y-8=\frac{1}{3}x-2 \end{gathered}[/tex]
-add 8 to both sides of it
[tex]\begin{gathered} y-8+8=\frac{1}{3}x-2+8 \\ y=\frac{1}{3}x+6 \end{gathered}[/tex]
The y-intercept of the line is the constant of the equation b=6
Plot both points and link them to graph the line:
