hel0 me 9ut pleàse[tex]f(x) = 4{x}^{2} - 3x[/tex][tex]find \: f( - 3)[/tex]

We have the function f(x)
[tex]f(x)=4x^2-3x[/tex]We are asked to find f(-3), let's solve it
[tex]\begin{gathered} f(-3)=4(-3)^2-3(-3) \\ f(-3)=4\cdot9+9 \\ f(-3)=36+9 \\ f(-3)=45 \end{gathered}[/tex]In conclusion, the answer is f(3) = 45