The recursive formula is
a = 57 ------- first term and d = -3 ------- common difference
[tex]a_n=-3+a_{n-1}[/tex]The explicit formula of the sequence is
[tex]a_n=a+(n-1)d[/tex]Where d is the constant difference between each 2 consecutive terms
∵ a is the first term
∴ a = 57
∵ d is the constant difference
∴ d = -3
→ Substitute them in the form above
[tex]\therefore a_n=57+(n-1)\times(-3)[/tex]Let us simplify it
[tex]\begin{gathered} \because a_n=57+n(-3)-1(-3) \\ \therefore a_n=57-3n+3 \\ \therefore a_n=(57+3)-3n \\ \therefore a_n=60-3n \end{gathered}[/tex]Then the explicit formula is an = 60 - 3n