We are given a set of definite integrals and we are tasked to find the area of the curve from x = 0 to 2.
To do this, we need to recall the adding intervals rules for definite integrals:
[tex]\int_a^bf(x)dx+\int_b^cf(x)dx=\int_a^cf(x)dx[/tex]Plugging in the given, we have the following equation:
[tex]\begin{gathered} \int_{-2}^2f(x)dx+\int_0^4f(x)dx-\int_0^2f(x)dx=\int_{-2}^4f(x)dx \\ \\ 7+(-3)-\int_0^2f(x)dx=2 \\ \\ -\int_0^2f(x)dx=-2 \\ \\ \int_0^2f(x)dx=2 \end{gathered}[/tex]The answer is 2.