to determine wether the system has one solution, an infinite number of solutions or no solution at all we have to solve it.
We have the system:
[tex]\begin{gathered} x-12y=-4 \\ x-9y=7 \end{gathered}[/tex]Substracting the second equation from the first one we have:
[tex]\begin{gathered} (x-12y)-(x-9y)=-4-7 \\ x-12y-x+9y=-11 \\ -3y=-11 \\ y=\frac{11}{3} \end{gathered}[/tex]Since we can find a value for the variable y we conclude that the system has only one solution.
The value of x can be found from the first equation once we have y:
[tex]\begin{gathered} x-12(\frac{11}{3})=-4 \\ x-44=-4 \\ x=44-4 \\ x=40 \end{gathered}[/tex]The solution of the sytem is x=40 and y=11/3.