Respuesta :

First, you can sum 6 on both sides of the equation, like this

[tex]\begin{gathered} \frac{5x-1}{3}-6=4x+2 \\ \frac{5x-1}{3}-6+6=4x+2+6 \\ \frac{5x-1}{3}=4x+8 \end{gathered}[/tex]

Then, you can multiply by 3 on both sides of the equation, like this

[tex]\begin{gathered} \frac{5x-1}{3}\cdot3=(4x+8)\cdot3 \\ 5x-1=12x+24 \end{gathered}[/tex]

Now, you can sum 1 on both sides of the equation

[tex]\begin{gathered} 5x-1=12x+24 \\ 5x-1+1=12x+24+1 \\ 5x=12x+25 \end{gathered}[/tex]

And now you can subtract 12x from both sides of the equation

[tex]\begin{gathered} 5x=12x+25 \\ 5x-12x=12x+25-12x \\ -7x=25 \end{gathered}[/tex]

Finally, you can divide by -7x on both sides of the equation

[tex]\begin{gathered} \frac{-7x}{-7}=\frac{25}{-7} \\ x=-\frac{25}{7} \end{gathered}[/tex]

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