ANSWER
2775
EXPLANATION
We have to find how many combinations of two people are possible since order does not matter. This is because both people will win a ticket, it does not matter which one is picked first,
[tex]_2C_{75}=\frac{75!}{2!(75-2)!}=\frac{75!}{2!\cdot73!}=\frac{75\cdot74\cdot73!}{2!\cdot73!}=\frac{75\cdot74}{2}=2775[/tex]Hence, 2775 groups of two people are possible.